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53462f0f47
One of the more common cases of allocation size calculations is finding
the size of a structure that has a zero-sized array at the end, along
with memory for some number of elements for that array. For example:
struct foo {
int stuff;
struct boo entry[];
};
size = sizeof(struct foo) + count * sizeof(struct boo);
Instead of leaving these open-coded and prone to type mistakes, we can
now use the new struct_size() helper:
size = struct_size(instance, entry, count);
This code was detected with the help of Coccinelle.
Signed-off-by: "Gustavo A. R. Silva" <gustavo@embeddedor.com>
Tested-by: Andrew Bowers <andrewx.bowers@intel.com>
Signed-off-by: Jeff Kirsher <jeffrey.t.kirsher@intel.com>
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| .. | ||
| i40e_adminq_cmd.h | ||
| i40e_adminq.c | ||
| i40e_adminq.h | ||
| iavf_alloc.h | ||
| iavf_client.c | ||
| iavf_client.h | ||
| iavf_common.c | ||
| iavf_devids.h | ||
| iavf_ethtool.c | ||
| iavf_main.c | ||
| iavf_osdep.h | ||
| iavf_prototype.h | ||
| iavf_register.h | ||
| iavf_status.h | ||
| iavf_trace.h | ||
| iavf_txrx.c | ||
| iavf_txrx.h | ||
| iavf_type.h | ||
| iavf_virtchnl.c | ||
| iavf.h | ||
| Makefile | ||