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394f56fe48
The theory behind vdso randomization is that it's mapped at a random offset above the top of the stack. To avoid wasting a page of memory for an extra page table, the vdso isn't supposed to extend past the lowest PMD into which it can fit. Other than that, the address should be a uniformly distributed address that meets all of the alignment requirements. The current algorithm is buggy: the vdso has about a 50% probability of being at the very end of a PMD. The current algorithm also has a decent chance of failing outright due to incorrect handling of the case where the top of the stack is near the top of its PMD. This fixes the implementation. The paxtest estimate of vdso "randomisation" improves from 11 bits to 18 bits. (Disclaimer: I don't know what the paxtest code is actually calculating.) It's worth noting that this algorithm is inherently biased: the vdso is more likely to end up near the end of its PMD than near the beginning. Ideally we would either nix the PMD sharing requirement or jointly randomize the vdso and the stack to reduce the bias. In the mean time, this is a considerable improvement with basically no risk of compatibility issues, since the allowed outputs of the algorithm are unchanged. As an easy test, doing this: for i in `seq 10000` do grep -P vdso /proc/self/maps |cut -d- -f1 done |sort |uniq -d used to produce lots of output (1445 lines on my most recent run). A tiny subset looks like this: 7fffdfffe000 7fffe01fe000 7fffe05fe000 7fffe07fe000 7fffe09fe000 7fffe0bfe000 7fffe0dfe000 Note the suspicious fe000 endings. With the fix, I get a much more palatable 76 repeated addresses. Reviewed-by: Kees Cook <keescook@chromium.org> Cc: stable@vger.kernel.org Signed-off-by: Andy Lutomirski <luto@amacapital.net> |
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