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x86/fpu: Use 'struct fpu' in fpu__copy()
Migrate this function to pure 'struct fpu' usage. Reviewed-by: Borislav Petkov <bp@alien8.de> Cc: Andy Lutomirski <luto@amacapital.net> Cc: Dave Hansen <dave.hansen@linux.intel.com> Cc: Fenghua Yu <fenghua.yu@intel.com> Cc: H. Peter Anvin <hpa@zytor.com> Cc: Linus Torvalds <torvalds@linux-foundation.org> Cc: Oleg Nesterov <oleg@redhat.com> Cc: Peter Zijlstra <peterz@infradead.org> Cc: Thomas Gleixner <tglx@linutronix.de> Signed-off-by: Ingo Molnar <mingo@kernel.org>
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@ -535,7 +535,7 @@ extern void fpstate_cache_init(void);
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extern int fpstate_alloc(struct fpu *fpu);
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extern void fpstate_free(struct fpu *fpu);
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extern int fpu__copy(struct task_struct *dst, struct task_struct *src);
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extern int fpu__copy(struct fpu *dst_fpu, struct fpu *src_fpu);
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static inline unsigned long
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alloc_mathframe(unsigned long sp, int ia32_frame, unsigned long *buf_fx,
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@ -240,15 +240,12 @@ static void fpu_copy(struct fpu *dst_fpu, struct fpu *src_fpu)
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}
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}
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int fpu__copy(struct task_struct *dst, struct task_struct *src)
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int fpu__copy(struct fpu *dst_fpu, struct fpu *src_fpu)
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{
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struct fpu *dst_fpu = &dst->thread.fpu;
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struct fpu *src_fpu = &src->thread.fpu;
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dst->thread.fpu.counter = 0;
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dst->thread.fpu.has_fpu = 0;
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dst->thread.fpu.state = NULL;
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dst->thread.fpu.last_cpu = -1;
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dst_fpu->counter = 0;
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dst_fpu->has_fpu = 0;
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dst_fpu->state = NULL;
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dst_fpu->last_cpu = -1;
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if (src_fpu->fpstate_active) {
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int err = fpstate_alloc(dst_fpu);
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@ -83,7 +83,7 @@ int arch_dup_task_struct(struct task_struct *dst, struct task_struct *src)
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{
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*dst = *src;
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return fpu__copy(dst, src);
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return fpu__copy(&dst->thread.fpu, &src->thread.fpu);
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}
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void arch_release_task_struct(struct task_struct *tsk)
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