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stacktrace: Don't skip first entry on noncurrent tasks
When doing cat /proc/<PID>/stack, the output is missing the first entry. When the current code walks the stack starting in stack_trace_save_tsk, it skips all scheduler functions (that's OK) plus one more function. But this one function should be skipped only for the 'current' task as it is stack_trace_save_tsk proper. The original code (before the common infrastructure) skipped one function only for the 'current' task -- see save_stack_trace_tsk before3599fe12a1
. So do so also in the new infrastructure now. Fixes:214d8ca6ee
("stacktrace: Provide common infrastructure") Signed-off-by: Jiri Slaby <jslaby@suse.cz> Signed-off-by: Thomas Gleixner <tglx@linutronix.de> Tested-by: Michal Suchanek <msuchanek@suse.de> Acked-by: Josh Poimboeuf <jpoimboe@redhat.com> Link: https://lkml.kernel.org/r/20191030072545.19462-1-jslaby@suse.cz
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@ -141,7 +141,8 @@ unsigned int stack_trace_save_tsk(struct task_struct *tsk, unsigned long *store,
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struct stacktrace_cookie c = {
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.store = store,
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.size = size,
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.skip = skipnr + 1,
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/* skip this function if they are tracing us */
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.skip = skipnr + !!(current == tsk),
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};
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if (!try_get_task_stack(tsk))
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@ -298,7 +299,8 @@ unsigned int stack_trace_save_tsk(struct task_struct *task,
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struct stack_trace trace = {
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.entries = store,
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.max_entries = size,
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.skip = skipnr + 1,
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/* skip this function if they are tracing us */
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.skip = skipnr + !!(current == task),
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};
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save_stack_trace_tsk(task, &trace);
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