i40e: amortize wait time when disabling lots of VFs

Just as we do in i40e_reset_all_vfs, save some time when freeing VFs by
amortizing the wait time for stopping queues. We can use
i40e_vsi_stop_rings_no_wait() to begin the process of stopping all the
VF rings at once. Then, once we've started the process on each VF we can
begin waiting for the VFs to stop. This helps reduce the total wait time
by a large factor.

Signed-off-by: Jacob Keller <jacob.e.keller@intel.com>
Tested-by: Andrew Bowers <andrewx.bowers@intel.com>
Signed-off-by: Jeff Kirsher <jeffrey.t.kirsher@intel.com>
This commit is contained in:
Jacob Keller 2017-04-19 09:25:52 -04:00 committed by Jeff Kirsher
parent 1f190d9369
commit 707d088af3

View File

@ -1194,9 +1194,21 @@ void i40e_free_vfs(struct i40e_pf *pf)
usleep_range(1000, 2000);
i40e_notify_client_of_vf_enable(pf, 0);
for (i = 0; i < pf->num_alloc_vfs; i++)
/* Amortize wait time by stopping all VFs at the same time */
for (i = 0; i < pf->num_alloc_vfs; i++) {
if (test_bit(I40E_VF_STATE_INIT, &pf->vf[i].vf_states))
i40e_vsi_stop_rings(pf->vsi[pf->vf[i].lan_vsi_idx]);
continue;
i40e_vsi_stop_rings_no_wait(pf->vsi[pf->vf[i].lan_vsi_idx]);
}
for (i = 0; i < pf->num_alloc_vfs; i++) {
if (test_bit(I40E_VF_STATE_INIT, &pf->vf[i].vf_states))
continue;
i40e_vsi_wait_queues_disabled(pf->vsi[pf->vf[i].lan_vsi_idx]);
}
/* Disable IOV before freeing resources. This lets any VF drivers
* running in the host get themselves cleaned up before we yank