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x86-64, NUMA: Do not scan two times for setup_node_bootmem()
By the time setup_node_bootmem() is called, all the memblocks are already registered. As node_data is allocated from these memblocks, calling it more than once doesn't make any difference. Drop the loop. tj: Dropped comment referencing to the old behavior as suggested by David and rephrased the description. Signed-off-by: Yinghai Lu <yinghai@kernel.org> Acked-by: David Rientjes <rientjes@google.com> Signed-off-by: Tejun Heo <tj@kernel.org>
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@ -480,7 +480,7 @@ static bool __init numa_meminfo_cover_memory(const struct numa_meminfo *mi)
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static int __init numa_register_memblks(struct numa_meminfo *mi)
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{
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int i, j, nid;
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int i, nid;
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/* Account for nodes with cpus and no memory */
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node_possible_map = numa_nodes_parsed;
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@ -506,28 +506,20 @@ static int __init numa_register_memblks(struct numa_meminfo *mi)
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init_memory_mapping_high();
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/*
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* Finally register nodes. Do it twice in case setup_node_bootmem
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* missed one due to missing bootmem.
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*/
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for (i = 0; i < 2; i++) {
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for_each_node_mask(nid, node_possible_map) {
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u64 start = (u64)max_pfn << PAGE_SHIFT;
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u64 end = 0;
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/* Finally register nodes. */
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for_each_node_mask(nid, node_possible_map) {
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u64 start = (u64)max_pfn << PAGE_SHIFT;
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u64 end = 0;
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if (node_online(nid))
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for (i = 0; i < mi->nr_blks; i++) {
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if (nid != mi->blk[i].nid)
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continue;
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for (j = 0; j < mi->nr_blks; j++) {
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if (nid != mi->blk[j].nid)
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continue;
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start = min(mi->blk[j].start, start);
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end = max(mi->blk[j].end, end);
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}
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if (start < end)
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setup_node_bootmem(nid, start, end);
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start = min(mi->blk[i].start, start);
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end = max(mi->blk[i].end, end);
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}
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if (start < end)
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setup_node_bootmem(nid, start, end);
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}
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return 0;
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