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cfg80211: Fix sanity check on 5 GHz when processing country IE

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This fixes two issues with the sanity check loop when processing
the country IE:

1. Do not use frequency for the current subband channel check,
   this was a big fat typo.
2. Apply the 5 GHz 4-channel steps when considering max channel
   on each subband as was done with a recent patch.

Signed-off-by: Luis R. Rodriguez <lrodriguez@atheros.com>
Signed-off-by: John W. Linville <linville@tuxdriver.com>
This commit is contained in:
Luis R. Rodriguez 2009-01-22 15:05:46 -08:00 committed by John W. Linville
parent 1f304e4e3b
commit 615aab4b75
1 changed files with 19 additions and 11 deletions
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30
net/wireless/reg.c
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@ -498,6 +498,7 @@ static struct ieee80211_regdomain *country_ie_2_rd(
* calculate the number of reg rules we will need. We will need one
* for each channel subband */
while (country_ie_len >= 3) {
int end_channel = 0;
struct ieee80211_country_ie_triplet *triplet =
(struct ieee80211_country_ie_triplet *) country_ie;
int cur_sub_max_channel = 0, cur_channel = 0;
@ -509,9 +510,25 @@ static struct ieee80211_regdomain *country_ie_2_rd(
continue;
}
/* 2 GHz */
if (triplet->chans.first_channel <= 14)
end_channel = triplet->chans.first_channel +
triplet->chans.num_channels;
else
/*
* 5 GHz -- For example in country IEs if the first
* channel given is 36 and the number of channels is 4
* then the individual channel numbers defined for the
* 5 GHz PHY by these parameters are: 36, 40, 44, and 48
* and not 36, 37, 38, 39.
*
* See: http://tinyurl.com/11d-clarification
*/
end_channel = triplet->chans.first_channel +
(4 * (triplet->chans.num_channels - 1));
cur_channel = triplet->chans.first_channel;
cur_sub_max_channel = ieee80211_channel_to_frequency(
cur_channel + triplet->chans.num_channels);
cur_sub_max_channel = end_channel;
/* Basic sanity check */
if (cur_sub_max_channel < cur_channel)
@ -590,15 +607,6 @@ static struct ieee80211_regdomain *country_ie_2_rd(
end_channel = triplet->chans.first_channel +
triplet->chans.num_channels;
else
/*
* 5 GHz -- For example in country IEs if the first
* channel given is 36 and the number of channels is 4
* then the individual channel numbers defined for the
* 5 GHz PHY by these parameters are: 36, 40, 44, and 48
* and not 36, 37, 38, 39.
*
* See: http://tinyurl.com/11d-clarification
*/
end_channel = triplet->chans.first_channel +
(4 * (triplet->chans.num_channels - 1));