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x86: Use correct byte-sized register constraint in __xchg_op()
x86-64 can access the low half of any register, but i386 can only do it with a subset of registers. 'r' causes compilation failures on i386, but 'q' expresses the constraint properly. Signed-off-by: Jeremy Fitzhardinge <jeremy@goop.org> Link: http://lkml.kernel.org/r/4F7A3315.501@goop.org Reported-by: Leigh Scott <leigh123linux@googlemail.com> Tested-by: Thomas Reitmayr <treitmayr@devbase.at> Signed-off-by: H. Peter Anvin <hpa@zytor.com> Cc: <stable@vger.kernel.org> v3.3
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@ -43,7 +43,7 @@ extern void __add_wrong_size(void)
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switch (sizeof(*(ptr))) { \
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case __X86_CASE_B: \
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asm volatile (lock #op "b %b0, %1\n" \
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: "+r" (__ret), "+m" (*(ptr)) \
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: "+q" (__ret), "+m" (*(ptr)) \
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: : "memory", "cc"); \
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break; \
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case __X86_CASE_W: \
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