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lmb: Add lmb_free()
We can free memory allocated with lmb_alloc() by removing it from the list of reserved LMBs. Rework lmb_remove() to allow that possibility and add lmb_free() which exploits it. BenH: Removed some useless parenthesis Signed-off-by: Michael Ellerman <michael@ellerman.id.au> Signed-off-by: Benjamin Herrenschmidt <benh@kernel.crashing.org>
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@ -42,6 +42,7 @@ extern void __init lmb_init(void);
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extern void __init lmb_analyze(void);
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extern long lmb_add(u64 base, u64 size);
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extern long lmb_remove(u64 base, u64 size);
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extern long __init lmb_free(u64 base, u64 size);
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extern long __init lmb_reserve(u64 base, u64 size);
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extern u64 __init lmb_alloc_nid(u64 size, u64 align, int nid,
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u64 (*nid_range)(u64, u64, int *));
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13
lib/lmb.c
13
lib/lmb.c
@ -205,9 +205,8 @@ long lmb_add(u64 base, u64 size)
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}
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long lmb_remove(u64 base, u64 size)
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static long __lmb_remove(struct lmb_region *rgn, u64 base, u64 size)
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{
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struct lmb_region *rgn = &(lmb.memory);
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u64 rgnbegin, rgnend;
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u64 end = base + size;
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int i;
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@ -254,6 +253,16 @@ long lmb_remove(u64 base, u64 size)
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return lmb_add_region(rgn, end, rgnend - end);
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}
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long lmb_remove(u64 base, u64 size)
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{
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return __lmb_remove(&lmb.memory, base, size);
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}
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long __init lmb_free(u64 base, u64 size)
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{
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return __lmb_remove(&lmb.reserved, base, size);
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}
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long __init lmb_reserve(u64 base, u64 size)
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{
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struct lmb_region *_rgn = &lmb.reserved;
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